a x^{2}-10 x+25=0

Question

a x^{2}-10 x+25=0

Accepted Answer

Step:1 ：Given the quadratic equation: (x^{2}-10x+25=0)Step:2 ：Use the quadratic formula: (x = frac{-b pm sqrt{b^{2} - 4ac}}{2a})Step:3 ：Substitute the coefficients: a = 1, b = -10, and c = 25Step:4 ：Calculate the discriminant: (Delta = b^{2} - 4ac = (-10)^{2} - 4(1)(25) = 100 - 100 = 0)Step:5 ：Substitute the discriminant and coefficients into the quadratic formula: (x = frac{-(-10) pm sqrt{0}}{2(1)})Step:6 ：(x = frac{10 pm 0}{2})Step:7 ：(boxed{x = 5})

Answer

Step: 1 ：Given the quadratic equation: (x^{2}-10x+25=0)Step: 2 ：Use the quadratic formula: (x = frac{-b pm sqrt{b^{2} - 4ac}}{2a})Step: 3 ：Substitute the coefficients: a = 1, b = -10, and c = 25Step: 4 ：Calculate the discriminant: (Delta = b^{2} - 4ac = (-10)^{2} - 4(1)(25) = 100 - 100 = 0)Step: 5 ：Substitute the discriminant and coefficients into the quadratic formula: (x = frac{-(-10) pm sqrt{0}}{2(1)})Step: 6 ：(x = frac{10 pm 0}{2})Step: 7 ：(boxed{x = 5})

a $x^{2} - 10 x + 25 = 0$

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a x2−10x+25=0

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a $x^{2} - 10 x + 25 = 0$