a) $x^{2}-2=2 x-4$
\(\boxed{x \approx 2.732, x \approx -0.732}\)
Step 1 :Rewrite the equation in the standard form: \(x^2 - 2x - 2 = 0\)
Step 2 :Use the quadratic formula: \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), where \(a = 1\), \(b = -2\), and \(c = -2\)
Step 3 :Calculate the discriminant: \(\Delta = b^2 - 4ac = 12\)
Step 4 :Find the solutions for x: \(x \approx 2.732\) and \(x \approx -0.732\)
Step 5 :\(\boxed{x \approx 2.732, x \approx -0.732}\)