1. Find the equation ( in factored form) of the quadratic relation with x-intercepts of -2 and 4 and y-intercept of -5 . Step 1) Sub in the numbers given for x and y intercepts. Step 2) Solve for a Step 3) Write the equation with number for ' a '

Question

1. Find the equation ( in factored form) of the quadratic relation with x-intercepts of -2 and 4 and y-intercept of -5 . Step 1) Sub in the numbers given for x and y intercepts. Step 2) Solve for a Step 3) Write the equation with number for &#x27; a &#x27;

Accepted Answer

Step:1 ：Given x-intercepts: x1 = -2, x2 = 4 and y-intercept: y = -5Step:2 ：Factored form of quadratic equation: y = a(x - x1)(x - x2)Step:3 ：Substitute x-intercepts and y-intercept: -5 = a(0 - -2)(0 - 4)Step:4 ：Solve for a: a = 0.625Step:5 ：Write the equation with the value of a: (boxed{y = 0.625(x + 2)(x - 4)})

Answer

Step: 1 ：Given x-intercepts: x1 = -2, x2 = 4 and y-intercept: y = -5Step: 2 ：Factored form of quadratic equation: y = a(x - x1)(x - x2)Step: 3 ：Substitute x-intercepts and y-intercept: -5 = a(0 - -2)(0 - 4)Step: 4 ：Solve for a: a = 0.625Step: 5 ：Write the equation with the value of a: (boxed{y = 0.625(x + 2)(x - 4)})

1. Find the equation ( in factored form) of the quadratic relation with $x$-intercepts of -2 and 4 and $y$-intercept of -5 . Step 1) Sub in the numbers given for $x$ and $y$ intercepts. Step 2) Solve for a Step 3) Write the equation with number for ' $a$ '

Answer

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