23.甲、乙二人练习跑步, 若甲让乙先跑10米, 则甲跑5秒可追上乙; 若乙比甲先跑2秒, 则甲跑4秒能追上乙。问: 两人每秒各跑多少米?
解: 甲乙速度差为 $10 / 5=2$

Answer

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Answer

$\boxed{\text{Final Answer: 甲每秒跑6米, 乙每秒跑4米}}$

Steps

Step 1 ：Form two equations based on the given information: $x = y + 2$ and $4x = 6y$

Step 2 ：Substitute the first equation into the second equation and solve for y: $(y + 2) * 4 = 6y$ to get $y = 4$

Step 3 ：Substitute the value of y back into the first equation to find x: $x = 4 + 2$ to get $x = 6$

Step 4 ：$\boxed{\text{Final Answer: 甲每秒跑6米, 乙每秒跑4米}}$