Problem

Find the equation of the tangent line to the function $f$ at $x=6$.
\[
f(x)=-9 x^{2}+3 x-8
\]
Show your work here
\[
y=
\]

Answer

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Answer

\boxed{y = -105x + 630}

Steps

Step 1 :Find the derivative of the function: \(f'(x) = -18x + 3\)

Step 2 :Evaluate the derivative at \(x = 6\): \(f'(6) = -105\)

Step 3 :Find the value of the function at \(x = 6\): \(f(6) = -314\)

Step 4 :Use the point-slope form to find the equation of the tangent line: \(y + 314 = -105(x - 6)\)

Step 5 :\boxed{y = -105x + 630}

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