Problem

A car moves in a straight line, at a time \( t_{1}=4 \mathrm{~s} \) after the start of the movement, the car is at \( x_{1}=54 \mathrm{~m} \), at \( \mathrm{t}_{2}=8 \mathrm{~s} \) after the start, it is at \( \times_{2}=255 \mathrm{~m} \) from the origin find the average velocity for the car

Answer

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Answer

\( \bar{v} = \frac{201 \mathrm{~m}}{4 \mathrm{~s}} = 50.25 \mathrm{\frac{m}{s}} \)

Steps

Step 1 :\( \bar{v} = \frac{\Delta x}{\Delta t} \)

Step 2 :\( \Delta x = x_{2} - x_{1} = 255 \mathrm{~m} - 54 \mathrm{~m} = 201 \mathrm{~m} \)

Step 3 :\( \Delta t = t_{2} - t_{1} = 8 \mathrm{~s} - 4 \mathrm{~s} = 4 \mathrm{~s} \)

Step 4 :\( \bar{v} = \frac{201 \mathrm{~m}}{4 \mathrm{~s}} = 50.25 \mathrm{\frac{m}{s}} \)

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