Problem

If the velocity of the object is given as \( V=12 t^{8}+3 t^{2} \) where \( x \) is in meters and \( t \) is in seconds. Find the instantaneous acceleration at \( 2 \mathrm{~S} \)

Answer

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Answer

\(\mathrm{Step~3:}~A(2) = 96(2)^7 + 6(2)\)

Steps

Step 1 :\(\mathrm{Step~1:}~\frac{dV}{dt} = A(t) = \frac{d(12t^{8} + 3t^2)}{dt}\)

Step 2 :\(\mathrm{Step~2:}~A(t) = 96t^7 + 6t\)

Step 3 :\(\mathrm{Step~3:}~A(2) = 96(2)^7 + 6(2)\)

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