Solve the exponential equation for \( x \).\[9^{3 x-10}=\left(\frac{1}{81}\right)^{\frac{1}{6}}\]
x=\frac{-1}{18}+\frac{10}{3}
Step 1 :9^{3x-10}=(81^{-1})^{\frac{1}{6}}
Step 2 :3x-10=\frac{1}{6}(-1)
Step 3 :x=\frac{-1}{18}+\frac{10}{3}