Problem

The position of a particle moving along x axis is given by x=1t3+8t2+35, find the instantaneous acceleration at 5 s

Answer

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Answer

a(5)=46

Steps

Step 1 :x(t)=t3+8t2+35

Step 2 :v(t)=dxdt=3t2+16t

Step 3 :a(t)=dvdt=6t+16

Step 4 :a(5)=6(5)+16

Step 5 :a(5)=46

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