Find \( \int\left(\frac{3}{\sqrt{x}}\right) d x \)
\(6\sqrt{x}+C\)
Step 1 :\int\left(\frac{3}{\sqrt{x}}\right) d x = 3\int\left(x^{-\frac{1}{2}}\right) d x
Step 2 :3\left(\frac{x^{\frac{1}{2}}}{\frac{1}{2}}+C\right)
Step 3 :\(6\sqrt{x}+C\)