Problem

Exercise 2:
A bag contains 10 chips. 3 of the chips are red, 5 of the chips are white, and 2 of the chips are blue. Three chips are selected, with replacement. Find the probability that you select ex actly one red chip.

Answer

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Answer

\(P(\text{exactly 1 red}) = \frac{9}{200} + \frac{75}{1000} + \frac{12}{1000} \)

Steps

Step 1 :\(P(\text{exactly 1 red}) = P(\text{RRW or WR or BR}) \)

Step 2 :\(P(\text{RRW}) = P(\text{R})^2 \cdot P(\text{W}) \)

Step 3 :\(P(\text{WR}) = P(\text{W})^2 \cdot P(\text{R}) \)

Step 4 :\(P(\text{BR}) = (1 - P(\text{W}) - P(\text{R}))^2 \cdot P(\text{R}) \)

Step 5 :\(P(RRW) = (\frac{3}{10})^2 \cdot \frac{5}{10} \)

Step 6 :\(P(WR) = (\frac{5}{10})^2 \cdot \frac{3}{10} \)

Step 7 :\(P(BR) = (1 - \frac{5}{10} - \frac{3}{10})^2 \cdot \frac{3}{10} \)

Step 8 :\(P(RRW) = (\frac{9}{100}) \cdot \frac{1}{2} \)

Step 9 :\(P(WR) = (\frac{25}{100}) \cdot \frac{3}{10} \)

Step 10 :\(P(BR) = (\frac{4}{100}) \cdot \frac{3}{10} \)

Step 11 :\(P(RRW) = \frac{9}{200} \)

Step 12 :\(P(WR) = \frac{75}{1000} \)

Step 13 :\(P(BR) = \frac{12}{1000} \)

Step 14 :\(P(\text{exactly 1 red}) = P(RRW) + P(WR) + P(BR) \)

Step 15 :\(P(\text{exactly 1 red}) = \frac{9}{200} + \frac{75}{1000} + \frac{12}{1000} \)

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