Find the slope of a line perpendicular to the line whose equation is \( 6 x+2 y=-32 \). Fully simplify your answer.
\( m_{\perp}=\frac{1}{3} \)
Step 1 :\( 6x+2y=-32 \)
Step 2 :\( y=-3x-16 \)
Step 3 :\( m=-3 \)
Step 4 :\( m_{\perp}=\frac{1}{3} \)