QUESTION 1
Quadratic Equation
Choose one $\cdot 5$ points
1. Solve $x^{2}+4 x-5=0$ using the quadratic formula
\[
x_{1}=1, x_{2}=-5
\]
\[
r_{1}=1, x_{2}=5
\]
\[
x_{1}=-1, x_{2}=-5
\]

Answer

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Answer

Final Answer: The solutions to the equation are $\boxed{x_{1}=-5, x_{2}=1}$

Steps

Step 1 ：Given the quadratic equation $x^{2}+4 x-5=0$

Step 2 ：Identify the coefficients as $a = 1$, $b = 4$, and $c = -5$

Step 3 ：Calculate the discriminant $D = b^2 - 4ac = 36$

Step 4 ：Use the quadratic formula to find the solutions for x: $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

Step 5 ：Substitute the values into the formula to get $x_1 = -5.0$ and $x_2 = 1.0$

Step 6 ：Final Answer: The solutions to the equation are $\boxed{x_{1}=-5, x_{2}=1}$