QUESTION 1
Quadratic Equation
Choose one $\cdot 5$ points
1. Solve $x^{2} + 4 x - 5 = 0$ using the quadratic formula
$x_{1} = 1, x_{2} = - 5$
$r_{1} = 1, x_{2} = 5$
$x_{1} = - 1, x_{2} = - 5$

Answer

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Answer

Final Answer: The solutions to the equation are $x_{1} = - 5, x_{2} = 1$

Steps

Step 1 ：Given the quadratic equation $x^{2} + 4 x - 5 = 0$

Step 2 ：Identify the coefficients as $a = 1$ , $b = 4$ , and $c = - 5$

Step 3 ：Calculate the discriminant $D = b^{2} - 4 a c = 36$

Step 4 ：Use the quadratic formula to find the solutions for x: $x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$

Step 5 ：Substitute the values into the formula to get $x_{1} = - 5.0$ and $x_{2} = 1.0$

Step 6 ：Final Answer: The solutions to the equation are $x_{1} = - 5, x_{2} = 1$