$\begin{array}{l}\frac{1}{2} x-\frac{2}{3} y=6 \\ \frac{1}{4} x+\frac{1}{3} y=-1\end{array}$
\(\boxed{x = 4, y = -6}\)
Step 1 :\(\frac{1}{2}x - \frac{2}{3}y = 6\) and \(\frac{1}{4}x + \frac{1}{3}y = -1\)
Step 2 :Multiply the second equation by 2 to make the coefficients of x the same: \(\frac{1}{2}x + \frac{2}{3}y = -2\)
Step 3 :Add the two equations: \(\frac{1}{2}x - \frac{2}{3}y + \frac{1}{2}x + \frac{2}{3}y = 6 - 2\)
Step 4 :Simplify: \(x = 4\)
Step 5 :Substitute x back into the first equation: \(\frac{1}{2}(4) - \frac{2}{3}y = 6\)
Step 6 :Simplify: \(2 - \frac{2}{3}y = 6\)
Step 7 :Subtract 2 from both sides: \(-\frac{2}{3}y = 4\)
Step 8 :Multiply both sides by \(-\frac{3}{2}\): \(y = -6\)
Step 9 :\(\boxed{x = 4, y = -6}\)