b) $\sqrt{x-1 \sqrt{2 x-2}}=2$
\(\boxed{x = 2, x = 9}\)
Step 1 :\(\sqrt{x-1 \sqrt{2 x-2}}=2\)
Step 2 :Square both sides: \(x-1 \sqrt{2 x-2} = 2^2 = 4\)
Step 3 :Move 4 to the left side: \(1 \sqrt{2 x-2} = x - 4\)
Step 4 :Square both sides again: \(2x - 2 = (x - 4)^2\)
Step 5 :Expand the right side: \(2x - 2 = x^2 - 8x + 16\)
Step 6 :Move all terms to the right side: \(x^2 - 10x + 18 = 0\)
Step 7 :Factor the quadratic: \((x - 2)(x - 9) = 0\)
Step 8 :Solve for x: \(x = 2\) or \(x = 9\)
Step 9 :Check the solutions: \(\sqrt{2-1 \sqrt{2 \cdot 2-2}}=2\) and \(\sqrt{9-1 \sqrt{2 \cdot 9-2}}=2\)
Step 10 :\(\boxed{x = 2, x = 9}\)