Based on Table G, what is the approximate mass of ${NH}_{3}$ that must be dissolved in 200 grams of water to produce a saturated solution at $20 .^{\circ} C$ ?
1. $28 g$
2. $56 g$
3. $100 g$
4. $112 g$

Answer

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Answer

$m_{2} = \frac{m_{1} \times s}{1 + s} = \frac{200 g \times \frac{112 g {NH}_{3}}{100 g H_{2} O}}{1 + \frac{112 g {NH}_{3}}{100 g H_{2} O}}$

Steps

Step 1 ： $m_{1} = 200 g$

Step 2 ： $s = \frac{112 g {NH}_{3}}{100 g H_{2} O}$

Step 3 ： $m_{2} = \frac{m_{1} \times s}{1 + s} = \frac{200 g \times \frac{112 g {NH}_{3}}{100 g H_{2} O}}{1 + \frac{112 g {NH}_{3}}{100 g H_{2} O}}$