Problem

Given the balanced equation representing a reaction:
$2 NaCl (ℓ) \to 2 Na (ℓ) + {Cl}_{2} (g)$
A 1170. -gram sample of $NaCl (ℓ)$ completely reacts, producing 460. grams of $Na (ℓ)$ . What is the total mass of ${Cl}_{2} (g)$ produced?
$1355 g$
2. 710. $g$
3. 1420. $g$
4. $1630 . g$

Answer

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Answer

$1170 g - 460 g = 710 g$

Steps

Step 1 ： $\frac{1170 g NaCl}{2 mol} \times \frac{58.44 g}{1 mol}$

Step 2 ： $\frac{460 g Na}{2 mol} \times \frac{22.99 g}{1 mol}$

Step 3 ： $1170 g - 460 g = 710 g$

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