Find the first four terms of the sequence with first term 7 and $n$th term $a_{n}=a_{n-1}+8$.
Answer
Final Answer: The first four terms of the sequence are \(\boxed{7, 15, 23, 31}\).
Step 1 ：The problem is asking for the first four terms of a sequence. The first term is given as 7, and each subsequent term is found by adding 8 to the previous term.
Step 2 ：We can find the first four terms by starting with the first term and applying the recursive formula three times.
Step 3 ：The first term is 7.
Step 4 ：The second term is \(a_{2} = a_{1} + 8 = 7 + 8 = 15\).
Step 5 ：The third term is \(a_{3} = a_{2} + 8 = 15 + 8 = 23\).
Step 6 ：The fourth term is \(a_{4} = a_{3} + 8 = 23 + 8 = 31\).
Step 7 ：Final Answer: The first four terms of the sequence are \(\boxed{7, 15, 23, 31}\).
