Find the inverse function of $f(x)=9+\sqrt[3]{x}$
\[
f^{-1}(x)=
\]
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$\boxed{f^{-1}(x) = 729.0*(0.111111111111111*x - 1)^3}$ is the inverse function of $f(x)=9+\sqrt[3]{x}$.

Steps

Step 1 ：To find the inverse of a function, we need to switch the roles of x and y (or f(x)) and solve for y. In this case, we need to solve the equation $x = 9 + y^{1/3}$ for y.

Step 2 ：Solving the equation gives us the inverse function as $f^{-1}(x) = 729.0*(0.111111111111111*x - 1)^3$.

Step 3 ：$\boxed{f^{-1}(x) = 729.0*(0.111111111111111*x - 1)^3}$ is the inverse function of $f(x)=9+\sqrt[3]{x}$.

Find the inverse function of $f(x)=9+\sqrt[3]{x}$\[f^{-1}(x)=\]$> $ Next Question

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Find the inverse function of $f(x)=9+\sqrt[3]{x}$
\[
f^{-1}(x)=
\]
$> $ Next Question