Problem

Question 14

Evaluate the indefinite integral
6sin4vcosvdv=

Answer

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Answer

Finally, the indefinite integral 6sin4vcosvdv is 1.2sin5v+C where C is the constant of integration.

Steps

Step 1 :Let's evaluate the indefinite integral 6sin4vcosvdv.

Step 2 :We can rewrite the integral as 6/5×du.

Step 3 :Here, u=sin(v)5 and du=5sin(v)4cos(v)dv.

Step 4 :Substituting these values, the integral simplifies to 1.2sin(v)5.

Step 5 :Finally, the indefinite integral 6sin4vcosvdv is 1.2sin5v+C where C is the constant of integration.

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