The lengths of mature trout in a local lake are approximately normally distributed with a mean of $μ = 12.5$ inches, and a standard deviation of $σ = 1.7$ inches.
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Find the $z$ -score corresponding to a fish that is 13.3 inches long. Round your answer to the nearest hundredth as needed.
$z =$

How long is a fish that has a z-score of 1.2 ? Round your answer to the nearest tenth as needed. inches
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Answer

$0.47$

Steps

Step 1 ：Calculate the z-score using the formula $z = \frac{(X - μ)}{σ}$

Step 2 ：Substitute the given values into the formula: $z = \frac{(13.3 - 12.5)}{1.7}$

Step 3 ：Simplify the expression to find the z-score

Step 4 ：Round the z-score to the nearest hundredth

Step 5 ： $0.47$