Problem

Find the endpoint of the square root function \(f(x) = \sqrt{x+2} - 3\)

Answer

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Answer

Step 3: Therefore, the endpoint of the square root function \(f(x) = \sqrt{x+2} - 3\) is (-2, -3)

Steps

Step 1 ：Step 1: To find the end point of the square root function, we first need to identify the domain. The domain of the square root function is all x such that \(x+2 \geq 0\) . So, we have \(x \geq -2\)

Step 2 ：Step 2: The range of the square root function is all y such that \(y \geq 0\). However, because of the -3 in the function, the range is translated downwards by three units. Therefore, the range is all y such that \(y \geq -3\)

Step 3 ：Step 3: Therefore, the endpoint of the square root function \(f(x) = \sqrt{x+2} - 3\) is (-2, -3)

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