Determine the center of the circle defined by the equation:
$(x-1)^{2}+(y+3)^{2}=4$
Final Answer: The center of the circle is \(\boxed{(1, -3)}\).
Step 1 :The equation of a circle in standard form is \((x-h)^2 + (y-k)^2 = r^2\), where \((h, k)\) is the center of the circle and r is the radius.
Step 2 :In the given equation, we can see that h = 1 and k = -3.
Step 3 :Therefore, the center of the circle is \((1, -3)\).
Step 4 :Final Answer: The center of the circle is \(\boxed{(1, -3)}\).