Problem

Determine the center of the circle defined by the equation:
$(x-1)^{2}+(y+3)^{2}=4$

Answer

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Answer

Final Answer: The center of the circle is \(\boxed{(1, -3)}\).

Steps

Step 1 :The equation of a circle in standard form is \((x-h)^2 + (y-k)^2 = r^2\), where \((h, k)\) is the center of the circle and r is the radius.

Step 2 :In the given equation, we can see that h = 1 and k = -3.

Step 3 :Therefore, the center of the circle is \((1, -3)\).

Step 4 :Final Answer: The center of the circle is \(\boxed{(1, -3)}\).

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