Problem

Evaluate the function at the given values.
\[
h(x)=x^{2}-6 x+2
\]
a. $h(2)$
b. $h(-2)$
c. $h(0)$

Answer

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Answer

So, the final answers are \(h(2) = \boxed{-6}\), \(h(-2) = \boxed{18}\), and \(h(0) = \boxed{2}\).

Steps

Step 1 :The function given is \(h(x)=x^{2}-6 x+2\).

Step 2 :We are asked to evaluate this function at the values \(x=2\), \(x=-2\), and \(x=0\).

Step 3 :First, let's substitute \(x=2\) into the function. This gives us \(h(2)=2^{2}-6*2+2=-6\).

Step 4 :Next, let's substitute \(x=-2\) into the function. This gives us \(h(-2)=(-2)^{2}-6*(-2)+2=18\).

Step 5 :Finally, let's substitute \(x=0\) into the function. This gives us \(h(0)=0^{2}-6*0+2=2\).

Step 6 :So, the final answers are \(h(2) = \boxed{-6}\), \(h(-2) = \boxed{18}\), and \(h(0) = \boxed{2}\).

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