You poured some $12\mathrm{\%}$ alcohol solution and some $6\mathrm{\%}$ alcohol solution into a mixing container. Now you have 480 grams of $8\mathrm{\%}$ alcohol solution. How many grams of $12\mathrm{\%}$ solution and how many grams of $6\mathrm{\%}$ solution did you pour into the mixing container?

Write and solve a system equation to answer the following questions.
You mixed $◻$ grams of $12\mathrm{\%}$ solution with $◻$ grams of $6\mathrm{\%}$ solution.

Step 1 ：Let's denote the amount of $12\mathrm{\%}$ solution as $x$ and the amount of $6\mathrm{\%}$ solution as $y$.

Step 2 ：From the problem, we know that the total amount of solution is 480 grams, so we have the equation $x+y=480$.

Step 3 ：We also know that the final solution is $8\mathrm{\%}$ alcohol, so the total amount of alcohol from the $12\mathrm{\%}$ solution and the $6\mathrm{\%}$ solution should be $8\mathrm{\%}$ of the total solution. This gives us the equation $0.12x+0.06y=0.08\times 480$.

Step 4 ：We can solve the first equation for $x$, which gives us $x=480-y$.

Step 5 ：Substitute $x=480-y$ into the second equation, we get $0.12(480-y)+0.06y=38.4$.

Step 6 ：Solving this equation for $y$, we get $y=320$.

Step 7 ：Substitute $y=320$ back into the first equation, we get $x=480-320=160$.

Step 8 ：So, the final answer is: You mixed $\boxed{{\displaystyle 160}}$ grams of $12\mathrm{\%}$ solution with $\boxed{{\displaystyle 320}}$ grams of $6\mathrm{\%}$ solution.