Determine whether the distribution is a discrete probability distribution.
\begin{tabular}{cc}
\hline $\mathbf{x}$ & $\mathrm{P}(\mathbf{x})$ ㅁ⼝ \\
\hline 0 & 0.26 \\
\hline 1 & 0.12 \\
\hline 2 & 0.21 \\
\hline 3 & 0.25 \\
\hline 4 & 0.16 \\
\hline
\end{tabular}

Is the distribution a discrete probability distribution?
A. Yes, because the sum of the probabilities is equal to 1.
B. Yes, because each probability is between 0 and 1 , inclusive.
C. No, because the-sum of the probabilities is not equal to 1.
D. Yes, because the sum of the probabilities is equal to 1 and each probability is between 0 and 1 , inclusive
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Step 1 ：Given the distribution table, we need to determine whether it is a discrete probability distribution. The conditions for a distribution to be a discrete probability distribution are: each probability is between 0 and 1, inclusive, and the sum of all probabilities is equal to 1.

Step 2 ：First, we check if each probability is between 0 and 1, inclusive. Looking at the table, we can see that all probabilities are indeed between 0 and 1.

Step 3 ：Next, we need to check if the sum of all probabilities is equal to 1. We do this by adding all the probabilities: \(0.26 + 0.12 + 0.21 + 0.25 + 0.16\).

Step 4 ：The sum of the probabilities is 1. Therefore, both conditions for a discrete probability distribution are met.

Step 5 ：Final Answer: \(\boxed{\text{(D) Yes, because the sum of the probabilities is equal to 1 and each probability is between 0 and 1 , inclusive}}\)