Find the magnitude and direction angle of the following vector. Write your angle in degrees rounded to four decimal places.
\[
\mathbf{u}=-11 \mathbf{i}+12 \mathbf{j}
\]

Step 1 ：Given the vector \(\mathbf{u}=-11 \mathbf{i}+12 \mathbf{j}\), we are to find the magnitude and direction angle of the vector.

Step 2 ：The magnitude of a vector \(\mathbf{u}=x \mathbf{i}+y \mathbf{j}\) is given by \(\|\mathbf{u}\|=\sqrt{x^2+y^2}\).

Step 3 ：Substituting \(x = -11\) and \(y = 12\) into the formula, we get \(\|\mathbf{u}\|=\sqrt{(-11)^2+(12)^2} \approx 16.2788\).

Step 4 ：The direction angle \(\theta\) of a vector \(\mathbf{u}=x \mathbf{i}+y \mathbf{j}\) is given by \(\theta = \arctan(\frac{y}{x})\).

Step 5 ：Substituting \(x = -11\) and \(y = 12\) into the formula, we get \(\theta = \arctan(\frac{12}{-11})\).

Step 6 ：Converting this angle from radians to degrees, we get \(\theta \approx 132.5104\) degrees.

Step 7 ：Final Answer: The magnitude of the vector is approximately \(\boxed{16.2788}\) and the direction angle of the vector is approximately \(\boxed{132.5104}\) degrees.