Find the magnitude and direction angle of the following vector. Write your angle in degrees rounded to four decimal places.
$$\mathbf{u}=-11\mathbf{i}+12\mathbf{j}$$

Step 1 ：Given the vector $\mathbf{u}=-11\mathbf{i}+12\mathbf{j}$, we are to find the magnitude and direction angle of the vector.

Step 2 ：The magnitude of a vector $\mathbf{u}=x\mathbf{i}+y\mathbf{j}$ is given by $\Vert \mathbf{u}\Vert =\sqrt{x^2+y^2}$.

Step 3 ：Substituting $x=-11$ and $y=12$ into the formula, we get $\Vert \mathbf{u}\Vert =\sqrt{(-11{)}^2+(12{)}^2}\approx 16.2788$.

Step 4 ：The direction angle $\theta$ of a vector $\mathbf{u}=x\mathbf{i}+y\mathbf{j}$ is given by $\theta =\arctan (\frac{y}{x})$.

Step 5 ：Substituting $x=-11$ and $y=12$ into the formula, we get $\theta =\arctan (\frac{12}{-11})$.

Step 6 ：Converting this angle from radians to degrees, we get $\theta \approx 132.5104$ degrees.

Step 7 ：Final Answer: The magnitude of the vector is approximately $\boxed{{\displaystyle 16.2788}}$ and the direction angle of the vector is approximately $\boxed{{\displaystyle 132.5104}}$ degrees.