How many ways can a committee of 7 be selected from a club with 15 members?

Step 1 ：We are given a club with 15 members and we are asked to find out how many ways a committee of 7 can be selected.

Step 2 ：This is a problem of combinations, where order does not matter. The formula for combinations is given by \( C(n, k) = \frac{n!}{k!(n-k)!} \), where \( n \) is the total number of items, \( k \) is the number of items to choose, and \( ! \) denotes factorial.

Step 3 ：Substituting the given values into the formula, we get \( C(15, 7) = \frac{15!}{7!(15-7)!} \).

Step 4 ：Calculating the factorials and simplifying the expression, we find that there are \(\boxed{6435}\) ways to select a committee of 7 from a club with 15 members.