Part 1 of 2
Points: 0.5 of 1
Find the $\mathrm{P}$-value for the indicated hypothesis test with the given standardized test statistic, $\mathrm{z}$. Decide whether to reject $\mathrm{H}_{0}$ for the given level of significance a Right-tailed test with test statistic $z=1.09$ and $\alpha=0.09$

P-value $=\square$ (Round to four decimal places as needed.)

Step 1 ：Given a right-tailed test with test statistic \(z=1.09\) and \(\alpha=0.09\).

Step 2 ：The P-value is the probability that a random chance generated the data, or something else that is equal or more extreme given that the null hypothesis is true.

Step 3 ：In a right-tailed test, the P-value is the area to the right of the test statistic (z-score) on the standard normal distribution curve.

Step 4 ：We can find this value using the cumulative distribution function (CDF) of the standard normal distribution. The CDF gives us the area to the left of the z-score, so to find the area to the right (which is the P-value in a right-tailed test), we subtract the CDF value from 1.

Step 5 ：Using this method, we find that the P-value is 0.1378565720320355, which rounds to 0.1379 when rounded to four decimal places.

Step 6 ：We reject the null hypothesis H0 if the P-value is less than or equal to the level of significance (\(\alpha\)). In this case, \(\alpha = 0.09\).

Step 7 ：Since the P-value is greater than \(\alpha\), we do not reject the null hypothesis H0.

Step 8 ：Final Answer: The P-value is \(\boxed{0.1379}\). We do not reject the null hypothesis \(\mathrm{H}_{0}\) because the P-value is greater than the level of significance \(\alpha\).