эpplicable, give the solution.
\begin{tabular}{|c|c|}
\hline \begin{tabular}{c}
System A \\
$-x-5 y=5$ \\
$x+5 y-5=0$
\end{tabular} & \begin{tabular}{l}
The system has no solution. \\
The system has a unique solution: \\
$(x, y)=$ \\
The system has infinitely many solutions. \\
They must satisfy the following equation: \\
$y=\square$
\end{tabular} \\
\hline \begin{tabular}{r}
System B \\
$-x+2 y=6$ \\
$x+2 y=6$
\end{tabular} & \begin{tabular}{l}
The system has no solution. \\
The system has a unique solution: \\
$(x, y)=$ \\
The system has infinitely many solutions. \\
They must satisfy the following equation: \\
$y=\square$
\end{tabular} \\
\hline
\end{tabular}
Explanation
Check

Step 1 ：We are given two systems of linear equations. System A consists of the equations -x - 5y = 5 and x + 5y - 5 = 0. System B consists of the equations -x + 2y = 6 and x + 2y = 6.

Step 2 ：We start by solving System A. After simplifying the equations, we find that they are contradictory, meaning that System A has no solution.

Step 3 ：Next, we solve System B. After simplifying the equations, we find that they are identical, meaning that System B has a unique solution.

Step 4 ：By substituting the value of x from the second equation of System B into the first equation, we find that y = 3.

Step 5 ：Substituting y = 3 back into the second equation of System B, we find that x = 0.

Step 6 ：Therefore, the solution to System B is \((x, y) = \boxed{(0, 3)}\).

Step 7 ：In conclusion, System A has no solution and System B has a unique solution \((x, y) = \boxed{(0, 3)}\).