16
The following data represent exam scores in a statistics class taught using traditional lecture and a class taught using a "flipped" classroom. Complete parts (a) through (c) below.
\begin{tabular}{llllllll}
\hline Traditional & 70.1 & 68.4 & 80.2 & 67.3 & 85.0 & 77.9 & 56.9 \\
& 81.2 & 80.7 & 70.5 & 64.3 & 70.7 & 60.7 & \\
\hline Flipped & 76.5 & 72.3 & 62.9 & 73.4 & 77.5 & 90.7 & 79.2 \\
& 77.2 & 82.2 & 70.4 & 91.2 & 77.4 & 77.5 & \\
\hline
\end{tabular}
(a) Which course has more dispersion in exam scores using the range as the measure of dispersion?

The traditional course has a range of while the "Tlipped" course has a range of The course has more dispersion.
(Type integers or decimals. Do not round.)

Step 1 ：Given the exam scores for a traditional and a flipped classroom, we are asked to determine which course has more dispersion in exam scores using the range as the measure of dispersion.

Step 2 ：The range is calculated as the difference between the maximum and minimum values.

Step 3 ：For the traditional course, the scores are: 70.1, 68.4, 80.2, 67.3, 85.0, 77.9, 56.9, 81.2, 80.7, 70.5, 64.3, 70.7, 60.7. The range of these scores is \(85.0 - 56.9 = 28.1\).

Step 4 ：For the flipped course, the scores are: 76.5, 72.3, 62.9, 73.4, 77.5, 90.7, 79.2, 77.2, 82.2, 70.4, 91.2, 77.4, 77.5. The range of these scores is \(91.2 - 62.9 = 28.3\).

Step 5 ：Comparing the ranges, we find that the flipped course has a larger range than the traditional course.

Step 6 ：\(\boxed{\text{Therefore, the flipped course has more dispersion in exam scores.}}\)