Suppose there are three pipes filling a tank.
The first pipe can fill the tank in 5 hours.
The second pipe can fill the tank in 8 hours.
The third pipe can fill the tank in 7 hours.
Suppose the pipes run for $5 \times 8 \times 7=280$ hours.
How many tanks can the first pipe fill?
How many tanks can the second pipe fill?
How many tanks can the third pipe fill?
Answer
Final Answer: The first pipe can fill \(\boxed{56}\) tanks.
Step 1 ：Suppose there are three pipes filling a tank. The first pipe can fill the tank in 5 hours. The second pipe can fill the tank in 8 hours. The third pipe can fill the tank in 7 hours.
Step 2 ：Suppose the pipes run for \(5 \times 8 \times 7=280\) hours.
Step 3 ：We are asked how many tanks the first pipe can fill. Since the first pipe can fill the tank in 5 hours, and the pipes run for 280 hours, we can calculate this by dividing the total hours by the hours needed for the first pipe.
Step 4 ：\(\frac{280}{5} = 56\)
Step 5 ：Final Answer: The first pipe can fill \(\boxed{56}\) tanks.
