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Suppose that the functions $h$ and $g$ are defined as follows.
$\begin{array}{l} h (x) = x + 6 \\ g (x) = (x - 4) (x - 2) \end{array}$
(a) Find $(\frac{h}{g}) (5)$ .
(b) Find all values that are NOT in the domain of $\frac{h}{g}$ If there is more than one value, separate them with commas.
(a) $(\frac{6}{3}) (5) = 0$

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Final Answer: (b) Value(s) that are NOT in the domain of $\frac{h}{g}$ : $2, 4$

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Step 1 ：For part (a), we need to find the value of $(\frac{h}{g}) (5)$ . This means we need to substitute $x = 5$ into the function $\frac{h (x)}{g (x)}$ .

Step 2 ：For part (b), the values that are not in the domain of $\frac{h}{g}$ are the values of $x$ for which $g (x) = 0$ , because division by zero is undefined in mathematics. So we need to solve the equation $g (x) = 0$ to find these values.

Step 3 ：Final Answer: (a) $(\frac{h}{g}) (5) = 0.5$

Step 4 ：Final Answer: (b) Value(s) that are NOT in the domain of $\frac{h}{g}$ : $2, 4$

2345Suppose that the functions h and g are defined as follows.h(x)=x+6g(x)=(x−4)(x−2)(a) Find (hg)(5).(b) Find all values that are NOT in the domain of hg If there is more than one value, separate them with commas.(a) (63)(5)=0

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