left(frac{5}{35}right)^{-2} cdotleft(2^{-2}right)

Question

Accepted Answer

Step:1 ：Simplify the fraction inside the parentheses in the first part of the expression, (left(frac{5}{35}right)^{-2}), to get (left(frac{1}{7}right)^{-2}).Step:2 ：Raise (frac{1}{7}) to the power of -2 to get 49.Step:3 ：Simplify the second part of the expression, (2^{-2}), to get (frac{1}{2^2}).Step:4 ：Simplify (frac{1}{2^2}) to get 0.25.Step:5 ：Finally, multiply the results of the two parts together to get the final answer, 49 * 0.25 = 12.25.Step:6 ：(boxed{12.25}) is the final answer.

Answer

Step: 1 ：Simplify the fraction inside the parentheses in the first part of the expression, (left(frac{5}{35}right)^{-2}), to get (left(frac{1}{7}right)^{-2}).Step: 2 ：Raise (frac{1}{7}) to the power of -2 to get 49.Step: 3 ：Simplify the second part of the expression, (2^{-2}), to get (frac{1}{2^2}).Step: 4 ：Simplify (frac{1}{2^2}) to get 0.25.Step: 5 ：Finally, multiply the results of the two parts together to get the final answer, 49 * 0.25 = 12.25.Step: 6 ：(boxed{12.25}) is the final answer.

$\left(\frac{5}{35}\right)^{-2} \cdot\left(2^{-2}\right)$

Answer

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