Solve the following system of equations using the elimination method.
$\begin{matrix} {\begin{cases} 6 x - 2 y = - 4 \\ 3 x + y = 4 \end{cases} \\ (\frac{[?]}{3}, []) \end{matrix}$

Answer

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Answer

$T h e s o l u t i o n t o t h e s y s t e m o f e q u a t i o n s i s (\frac{1}{3}, 3)$

Steps

Step 1 ：Multiply the second equation by 2 to get $6 x + 2 y = 8$

Step 2 ：Add the two equations together to get $12 x = 4$

Step 3 ：Divide both sides by 12 to solve for x, giving $x = \frac{1}{3}$

Step 4 ：Substitute $x = \frac{1}{3}$ into the second equation to get $3 * \frac{1}{3} + y = 4$

Step 5 ：Simplify to get $y = 3$

Step 6 ： $T h e s o l u t i o n t o t h e s y s t e m o f e q u a t i o n s i s (\frac{1}{3}, 3)$