Solve the following system of equations using the elimination method.
\[
\begin{array}{c}
\left\{\begin{array}{l}
6 x-2 y=-4 \\
3 x+y=4
\end{array}\right. \\
\left(\frac{[?]}{3},[]\right)
\end{array}
\]

Answer

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Answer

\(\boxed{The solution to the system of equations is \left(\frac{1}{3}, 3\right)}\)

Steps

Step 1 ：Multiply the second equation by 2 to get \(6x + 2y = 8\)

Step 2 ：Add the two equations together to get \(12x = 4\)

Step 3 ：Divide both sides by 12 to solve for x, giving \(x = \frac{1}{3}\)

Step 4 ：Substitute \(x = \frac{1}{3}\) into the second equation to get \(3*\frac{1}{3} + y = 4\)

Step 5 ：Simplify to get \(y = 3\)

Step 6 ：\(\boxed{The solution to the system of equations is \left(\frac{1}{3}, 3\right)}\)