Find an equation of the line having a slope of -1 and point $(6, - 2)$ .
Write the answer in slope-intercept form $y = m x + b$ .
$y =$

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Final Answer: The equation of the line is $y = - x + 4$ .

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Step 1 ：The equation of a line in slope-intercept form is given by $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

Step 2 ：We are given that the slope $m$ is -1 and the line passes through the point $(6, - 2)$ . We can substitute these values into the equation to find the y-intercept $b$ .

Step 3 ：Substituting the given values, we get $b = 4$ .

Step 4 ：Now that we have the slope and the y-intercept, we can substitute these values into the slope-intercept form to get the equation of the line.

Step 5 ：Substituting $m = - 1$ and $b = 4$ into the equation, we get $y = - 1 x + 4$ .

Step 6 ：Final Answer: The equation of the line is $y = - x + 4$ .

Find an equation of the line having a slope of -1 and point (6,−2).Write the answer in slope-intercept form y=mx+b.y=

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Find an equation of the line having a slope of -1 and point $(6, - 2)$ .
Write the answer in slope-intercept form $y = m x + b$ .
$y =$