Simplify the expression:
$\frac{(x-3)^{2}}{x} \div \frac{x^{2}-9}{2 x}=$

Answer

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Answer

Final Answer: $\boxed{\frac{2*(x - 3)}{x + 3}}$

Steps

Step 1 ：Rewrite the division as multiplication: $\frac{(x-3)^{2}}{x} \times \frac{2 x}{x^{2}-9}$

Step 2 ：Simplify the expression $(x-3)^{2}$ to $x^{2} - 6x + 9$

Step 3 ：Factor the expression $x^{2}-9$ to $(x-3)(x+3)$

Step 4 ：Substitute these simplifications into the expression: $\frac{x^{2} - 6x + 9}{x} \times \frac{2 x}{(x-3)(x+3)}$

Step 5 ：Simplify the expression to $\frac{2*(x - 3)}{x + 3}$

Step 6 ：Final Answer: $\boxed{\frac{2*(x - 3)}{x + 3}}$