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A line passes through the point $(- 8, - 9)$ and has a slope of 3 . Write an equation in slope-intercept form for this line.

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$T h e e q u a t i o n o f t h e l i n e i n s l o p e - i n t e r c e p t f o r m i s y = 3 x + 15$

Steps

Step 1 ：The slope-intercept form of a line is given by $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

Step 2 ：We know the slope $m$ is 3, and we have a point $(- 8, - 9)$ that the line passes through.

Step 3 ：We can substitute these values into the equation to solve for $b$ .

Step 4 ： $m = 3$

Step 5 ： $b = 15$

Step 6 ：Now that we have the slope and the y-intercept, we can write the equation of the line in slope-intercept form.

Step 7 ： $T h e e q u a t i o n o f t h e l i n e i n s l o p e - i n t e r c e p t f o r m i s y = 3 x + 15$