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A line passes through the point $(-8,-9)$ and has a slope of 3 . Write an equation in slope-intercept form for this line.
\(\boxed{The equation of the line in slope-intercept form is y = 3x + 15}\)
Step 1 :The slope-intercept form of a line is given by \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept.
Step 2 :We know the slope \(m\) is 3, and we have a point \((-8,-9)\) that the line passes through.
Step 3 :We can substitute these values into the equation to solve for \(b\).
Step 4 :\(m = 3\)
Step 5 :\(b = 15\)
Step 6 :Now that we have the slope and the y-intercept, we can write the equation of the line in slope-intercept form.
Step 7 :\(\boxed{The equation of the line in slope-intercept form is y = 3x + 15}\)