4 b^{2}+8 b+7=4

Question

4 b^{2}+8 b+7=4

Accepted Answer

Step:1 ：The given equation is a quadratic equation in the form of (ax^2 + bx + c = 0). We can solve this equation using the quadratic formula (x = frac{-b pm sqrt{b^2 - 4ac}}{2a}).Step:2 ：Identify the coefficients in the equation: (a = 4), (b = 8), and (c = 3).Step:3 ：Calculate the discriminant (D) using the formula (D = b^2 - 4ac). Substituting the values, we get (D = 16).Step:4 ：Substitute the values of a, b, and D into the quadratic formula to find the solutions. The solutions are (sol1 = -1.5) and (sol2 = -0.5).Step:5 ：The solutions to the equation (4 b^{2}+8 b+7=4) are (boxed{-1.5}) and (boxed{-0.5}).

Answer

Step: 1 ：The given equation is a quadratic equation in the form of (ax^2 + bx + c = 0). We can solve this equation using the quadratic formula (x = frac{-b pm sqrt{b^2 - 4ac}}{2a}).Step: 2 ：Identify the coefficients in the equation: (a = 4), (b = 8), and (c = 3).Step: 3 ：Calculate the discriminant (D) using the formula (D = b^2 - 4ac). Substituting the values, we get (D = 16).Step: 4 ：Substitute the values of a, b, and D into the quadratic formula to find the solutions. The solutions are (sol1 = -1.5) and (sol2 = -0.5).Step: 5 ：The solutions to the equation (4 b^{2}+8 b+7=4) are (boxed{-1.5}) and (boxed{-0.5}).

$4 b^{2} + 8 b + 7 = 4$

Answer

Popular Problems

4b2+8b+7=4

Answer

Popular Problems

$4 b^{2} + 8 b + 7 = 4$