$(6 \times(-6)) \div((-8)+(-2)-4+2) \div(-3)$

Step 1 ：Given the mathematical expression $(6 \times(-6)) \div((-8)+(-2)-4+2) \div(-3)$, we need to solve it according to the order of operations, which is parentheses, exponents, multiplication and division (from left to right), addition and subtraction (from left to right). This is often abbreviated as PEMDAS.

Step 2 ：First, perform the multiplication operation inside the parentheses: $(-36) \div((-8)+(-2)-4+2) \div(-3)$

Step 3 ：Next, perform the addition and subtraction operations inside the parentheses: $(-36) \div(-12) \div(-3)$

Step 4 ：Then, perform the division operation from left to right: $3 \div(-3)$

Step 5 ：Finally, perform the last division operation to get the result: $-1$

Step 6 ：So, the final answer is \(\boxed{-1.0}\)