Solving a percent mixture problem using a linear equation
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Two factory plants are making TV panels. Yesterday, Plant A produced 8000 panels. Four percent of the panels from Plant A and $1 %$ of the panels from Plant B were defective. How many panels did Plant B produce, if the overall percentage of defective panels from the two plants was $2 %$ ?
Number of panels produced by Plant B: \]
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Final Answer: $16000$

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Step 1 ：Let's denote the number of panels produced by Plant B as x. The total number of defective panels is the sum of the defective panels from Plant A and Plant B, which is $0.04 * 8000 + 0.01 * x$ . The total number of panels is $8000 + x$ .

Step 2 ：The overall percentage of defective panels is the total number of defective panels divided by the total number of panels, which is $(0.04 * 8000 + 0.01 * x) / (8000 + x) = 0.02$ .

Step 3 ：We can solve this equation for x.

Step 4 ：The solution to the equation is 16000. This means that Plant B produced 16000 panels.

Step 5 ：Final Answer: $16000$

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