2 1 point
What is the density in $\mathrm{g} / \mathrm{cm}^{3}$ of an unknown material if a cube of the material measures $3.60 \mathrm{~cm}$ on a side and has a mass of $3.19 \mathrm{~g}$ ? (you do not need to put in the units with your answer) Make sure vour answer is written to the correct number of significant figures to receive full credit.
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Step 1 ：The density of a material is calculated by the formula: Density = Mass / Volume.

Step 2 ：Given that the cube measures 3.60 cm on a side, the volume of the cube can be calculated using the formula for the volume of a cube: Volume = side^3.

Step 3 ：First, calculate the volume of the cube: \(3.60^3 = 46.656 \, \mathrm{cm^3}\).

Step 4 ：Then, use the calculated volume to find the density: \(\frac{3.19 \, \mathrm{g}}{46.656 \, \mathrm{cm^3}} = 0.06837277091906721 \, \mathrm{g/cm^3}\).

Step 5 ：However, the question asks for the answer to be written to the correct number of significant figures. The given values, 3.19 g and 3.60 cm, both have three significant figures. Therefore, the density should also be reported with three significant figures.

Step 6 ：Final Answer: The density of the unknown material is \(\boxed{0.068 \, \mathrm{g/cm^3}}\).