(e) Set the value of a to $-2,b$ to 2 , and $c$ to -1 . How many $x$-intercepts does the graph of the quadratic function have?
(Type a whole number.)

Step 1 ：Given the quadratic function $f(x)=a{x}^2+bx+c$, we are asked to find the number of x-intercepts. The x-intercepts of the graph of a function are the values of x for which the function equals zero. In other words, we need to solve the equation $a{x}^2+bx+c=0$ for x.

Step 2 ：The number of solutions to this equation (and hence the number of x-intercepts) is determined by the discriminant, $b^2-4ac$. If the discriminant is positive, there are two distinct solutions. If the discriminant is zero, there is one solution (or a repeated root). If the discriminant is negative, there are no real solutions, and hence no x-intercepts.

Step 3 ：Given that $a=-2$, $b=2$, and $c=-1$, we can calculate the discriminant as follows: $b^2-4ac=2^2-4(-2)(-1)=4-8=-4$.

Step 4 ：The discriminant is negative, which means there are no real solutions to the equation $a{x}^2+bx+c=0$. Therefore, the graph of the quadratic function has no x-intercepts.

Step 5 ：Final Answer: The graph of the quadratic function has $\boxed{{\displaystyle 0}}$ x-intercepts.