(e) Set the value of a to $-2, b$ to 2 , and $c$ to -1 . How many $x$-intercepts does the graph of the quadratic function have?
(Type a whole number.)

Step 1 ：Given the quadratic function \(f(x) = ax^2 + bx + c\), we are asked to find the number of x-intercepts. The x-intercepts of the graph of a function are the values of x for which the function equals zero. In other words, we need to solve the equation \(ax^2 + bx + c = 0\) for x.

Step 2 ：The number of solutions to this equation (and hence the number of x-intercepts) is determined by the discriminant, \(b^2 - 4ac\). If the discriminant is positive, there are two distinct solutions. If the discriminant is zero, there is one solution (or a repeated root). If the discriminant is negative, there are no real solutions, and hence no x-intercepts.

Step 3 ：Given that \(a = -2\), \(b = 2\), and \(c = -1\), we can calculate the discriminant as follows: \(b^2 - 4ac = 2^2 - 4(-2)(-1) = 4 - 8 = -4\).

Step 4 ：The discriminant is negative, which means there are no real solutions to the equation \(ax^2 + bx + c = 0\). Therefore, the graph of the quadratic function has no x-intercepts.

Step 5 ：Final Answer: The graph of the quadratic function has \(\boxed{0}\) x-intercepts.