24) frac{3 x+2}{10}-frac{1+6 x}{5} leq-frac{1}{2}

Question

Accepted Answer

Step:1 ：Rewrite the inequality as (frac{3 x+2}{10}-frac{2(1+6 x)}{10} leq -frac{1}{2})Step:2 ：Combine the fractions on the left side of the inequality to get (frac{3 x+2-2(1+6 x)}{10} leq -frac{1}{2})Step:3 ：Multiply both sides of the inequality by 10 to get rid of the denominator on the left side, resulting in (3 x+2-2(1+6 x) leq -5)Step:4 ：Solve the inequality for x to get x = 5/9Step:5 ：Check if the solution x = 5/9 satisfies the original inequalityStep:6 ：Since the solution x = 5/9 satisfies the original inequality, the solution to the inequality is (boxed{frac{5}{9}})

Answer

Step: 1 ：Rewrite the inequality as (frac{3 x+2}{10}-frac{2(1+6 x)}{10} leq -frac{1}{2})Step: 2 ：Combine the fractions on the left side of the inequality to get (frac{3 x+2-2(1+6 x)}{10} leq -frac{1}{2})Step: 3 ：Multiply both sides of the inequality by 10 to get rid of the denominator on the left side, resulting in (3 x+2-2(1+6 x) leq -5)Step: 4 ：Solve the inequality for x to get x = 5/9Step: 5 ：Check if the solution x = 5/9 satisfies the original inequalityStep: 6 ：Since the solution x = 5/9 satisfies the original inequality, the solution to the inequality is (boxed{frac{5}{9}})

24) $\frac{3 x + 2}{10} - \frac{1 + 6 x}{5} \leq - \frac{1}{2}$

Answer

Popular Problems

24) 3x+210−1+6x5≤−12

Answer

Popular Problems

24) $\frac{3 x + 2}{10} - \frac{1 + 6 x}{5} \leq - \frac{1}{2}$