If $f(1)=1$ and $f(n)=f(n-1)+2$ then find the value of $f(6)$.
Answer Attempt 1 out of 2

Step 1 ：Given that $f(1)=1$ and $f(n)=f(n-1)+2$

Step 2 ：We can use the given recursive formula to find $f(6)$

Step 3 ：First, find $f(2)$: $f(2)=f(2-1)+2=f(1)+2=1+2=3$

Step 4 ：Then, find $f(3)$: $f(3)=f(3-1)+2=f(2)+2=3+2=5$

Step 5 ：Next, find $f(4)$: $f(4)=f(4-1)+2=f(3)+2=5+2=7$

Step 6 ：After that, find $f(5)$: $f(5)=f(5-1)+2=f(4)+2=7+2=9$

Step 7 ：Finally, find $f(6)$: $f(6)=f(6-1)+2=f(5)+2=9+2=11$

Step 8 ：So, $f(6)=11$

Step 9 ：Check the result: $f(6)=f(5)+2=9+2=11$, which is consistent with the previous result

Step 10 ：Therefore, the final answer is $f(6)=\boxed{{\displaystyle 11}}$