$A=p\left(1+\frac{r}{n}\right)^{n t}$ when $p=200, r=0.04, n=1, t=3$

Step 1 ：We are given a compound interest formula: \(A=p\left(1+\frac{r}{n}\right)^{n t}\), where:

Step 2 ：- A is the amount of money accumulated after n years, including interest.

Step 3 ：- p is the principal amount (the initial amount of money).

Step 4 ：- r is the annual interest rate (in decimal).

Step 5 ：- n is the number of times that interest is compounded per year.

Step 6 ：- t is the time the money is invested for in years.

Step 7 ：We are given the values of p, r, n, and t as 200, 0.04, 1, and 3 respectively.

Step 8 ：Substitute these values into the formula to find the value of A: \(A=200\left(1+\frac{0.04}{1}\right)^{1 \times 3}\)

Step 9 ：Solving the above expression, we get A = 224.9728

Step 10 ：Final Answer: \(\boxed{224.9728}\)