$A=p{(1+\frac{r}{n})}^{nt}$ when $p=200,r=0.04,n=1,t=3$

Step 1 ：We are given a compound interest formula: $A=p{(1+\frac{r}{n})}^{nt}$, where:

Step 2 ：- A is the amount of money accumulated after n years, including interest.

Step 3 ：- p is the principal amount (the initial amount of money).

Step 4 ：- r is the annual interest rate (in decimal).

Step 5 ：- n is the number of times that interest is compounded per year.

Step 6 ：- t is the time the money is invested for in years.

Step 7 ：We are given the values of p, r, n, and t as 200, 0.04, 1, and 3 respectively.

Step 8 ：Substitute these values into the formula to find the value of A: $A=200{(1+\frac{0.04}{1})}^{1\times 3}$

Step 9 ：Solving the above expression, we get A = 224.9728

Step 10 ：Final Answer: $\boxed{{\displaystyle 224.9728}}$