Section 3.5
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Question 1
Find all zeros of the function $f(x)=4 x^{3}-52 x+48$. Enter the zeros separated by commas.
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Final Answer: The zeros of the function $f(x)=4 x^{3}-52 x+48$ are $\boxed{-4, 1, 3}$.

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Step 1 ：The question is asking to find the zeros of the function $f(x)=4 x^{3}-52 x+48$. The zeros of a function are the x-values for which the function equals zero. To find the zeros of this function, we need to solve the equation $4 x^{3}-52 x+48=0$.

Step 2 ：The zeros of the function are -4, 1, and 3. These are the x-values for which the function equals zero.

Step 3 ：Final Answer: The zeros of the function $f(x)=4 x^{3}-52 x+48$ are $\boxed{-4, 1, 3}$.

Section 3.5Score: $0 / 6 \quad 0 / 6$ answeredQuestion 1Find all zeros of the function $f(x)=4 x^{3}-52 x+48$. Enter the zeros separated by commas.Question Help: $\square$ VideoSubmit Question

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Section 3.5
Score: $0 / 6 \quad 0 / 6$ answered
Question 1
Find all zeros of the function $f(x)=4 x^{3}-52 x+48$. Enter the zeros separated by commas.
Question Help: $\square$ Video
Submit Question