Problem

Evaluate the following integral.
ln(3π/2)ln(11π/6)10evcosevdv

Answer

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Answer

The final answer is 53+35π6

Steps

Step 1 :Given the integral ln(3π/2)ln(11π/6)10evcosevdv

Step 2 :We can use the method of substitution. Let u=ev, then du=evdv=udv. So the integral becomes 10ucos(u)du from u=3π/2 to 11π/6

Step 3 :We can solve this integral by using the method of integration by parts, where we let u=u and dv=10cos(u)du. Then du=du and v=10sin(u)

Step 4 :The formula for integration by parts is udv=uvvdu

Step 5 :After calculating the integral, we substitute the limits of integration back in to get the final answer

Step 6 :The final answer is 53+35π6

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