frac{x}{(x+2)(x-2)}+frac{4}{x-2}=frac{3}{x+2}

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Accepted Answer

Step:1 ：Given the equation (frac{x}{(x+2)(x-2)}+frac{4}{x-2}=frac{3}{x+2})Step:2 ：First, we eliminate the fractions by multiplying each term by the common denominator, which is ((x+2)(x-2))Step:3 ：After simplifying, we get the equation (frac{3}{x + 2} = frac{5x + 8}{x^2 - 4})Step:4 ：Solving this equation, we find that the solution is (x = -7)Step:5 ：This means that when (x = -7), the equation holds trueStep:6 ：Final Answer: The solution to the equation is (boxed{-7})

Answer

Step: 1 ：Given the equation (frac{x}{(x+2)(x-2)}+frac{4}{x-2}=frac{3}{x+2})Step: 2 ：First, we eliminate the fractions by multiplying each term by the common denominator, which is ((x+2)(x-2))Step: 3 ：After simplifying, we get the equation (frac{3}{x + 2} = frac{5x + 8}{x^2 - 4})Step: 4 ：Solving this equation, we find that the solution is (x = -7)Step: 5 ：This means that when (x = -7), the equation holds trueStep: 6 ：Final Answer: The solution to the equation is (boxed{-7})

$\frac{x}{(x+2)(x-2)}+\frac{4}{x-2}=\frac{3}{x+2}$

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