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Find all angles, $0^{\circ} \leq \theta< 360^{\circ}$, that solve the following equation.
\[
\sin \theta=-\frac{\sqrt{2}}{2}
\]
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\[
\theta=
\]
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Final Answer: The solutions to the equation are \(\boxed{225^\circ}\) and \(\boxed{315^\circ}\).

Steps

Step 1 :The given equation is \(\sin \theta=-\frac{\sqrt{2}}{2}\).

Step 2 :We know that sine is negative in the third and fourth quadrants.

Step 3 :The reference angle for \(\frac{\sqrt{2}}{2}\) is \(45^\circ\).

Step 4 :So the solutions to the equation are \(180^\circ + 45^\circ\) and \(360^\circ - 45^\circ\).

Step 5 :angle1 = 225

Step 6 :angle2 = 315

Step 7 :Final Answer: The solutions to the equation are \(\boxed{225^\circ}\) and \(\boxed{315^\circ}\).

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